MENENTUKAN JUMLAH HOST & NETWORK ( DISKUSI ONLINE )
Tugas pertemuan 2 - Jerri mahanaim R Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini: 1.192.168.10.1/30 2.172.168.10.1/16 3.172.168.10.1/22 4.10.168.5.1/8 5.10.168.5.1/17 Jawaban Nomor 1: Netmask = 255.255.255.252 In binary = 11111111. 11111111. 11111111.11111100 Used to calculate = 11111100 Network = 2^n = 2^6 = 64 Network Host = 2^h-2 = 2^2-2 = 2 Host Nomor 2 : Netmask = 255.255.0.0 In Binary = 11111111.11111111.00000000.00000000 Used to calculate = 00000000.00000000 Network = 2^n = 2^0...